Optimal. Leaf size=34 \[ \frac {\tanh ^{-1}(\sin (a+b x))}{16 b}+\frac {\tan (a+b x) \sec (a+b x)}{16 b} \]
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Rubi [A] time = 0.04, antiderivative size = 34, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 3, integrand size = 20, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.150, Rules used = {4288, 3768, 3770} \[ \frac {\tanh ^{-1}(\sin (a+b x))}{16 b}+\frac {\tan (a+b x) \sec (a+b x)}{16 b} \]
Antiderivative was successfully verified.
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Rule 3768
Rule 3770
Rule 4288
Rubi steps
\begin {align*} \int \csc ^3(2 a+2 b x) \sin ^3(a+b x) \, dx &=\frac {1}{8} \int \sec ^3(a+b x) \, dx\\ &=\frac {\sec (a+b x) \tan (a+b x)}{16 b}+\frac {1}{16} \int \sec (a+b x) \, dx\\ &=\frac {\tanh ^{-1}(\sin (a+b x))}{16 b}+\frac {\sec (a+b x) \tan (a+b x)}{16 b}\\ \end {align*}
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Mathematica [A] time = 0.01, size = 38, normalized size = 1.12 \[ \frac {1}{8} \left (\frac {\tanh ^{-1}(\sin (a+b x))}{2 b}+\frac {\tan (a+b x) \sec (a+b x)}{2 b}\right ) \]
Antiderivative was successfully verified.
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fricas [B] time = 0.45, size = 61, normalized size = 1.79 \[ \frac {\cos \left (b x + a\right )^{2} \log \left (\sin \left (b x + a\right ) + 1\right ) - \cos \left (b x + a\right )^{2} \log \left (-\sin \left (b x + a\right ) + 1\right ) + 2 \, \sin \left (b x + a\right )}{32 \, b \cos \left (b x + a\right )^{2}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [B] time = 2.95, size = 1111, normalized size = 32.68 \[ \text {result too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 10.77, size = 38, normalized size = 1.12 \[ \frac {\sec \left (b x +a \right ) \tan \left (b x +a \right )}{16 b}+\frac {\ln \left (\sec \left (b x +a \right )+\tan \left (b x +a \right )\right )}{16 b} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [B] time = 0.47, size = 480, normalized size = 14.12 \[ \frac {4 \, {\left (\sin \left (3 \, b x + 3 \, a\right ) - \sin \left (b x + a\right )\right )} \cos \left (4 \, b x + 4 \, a\right ) - {\left (2 \, {\left (2 \, \cos \left (2 \, b x + 2 \, a\right ) + 1\right )} \cos \left (4 \, b x + 4 \, a\right ) + \cos \left (4 \, b x + 4 \, a\right )^{2} + 4 \, \cos \left (2 \, b x + 2 \, a\right )^{2} + \sin \left (4 \, b x + 4 \, a\right )^{2} + 4 \, \sin \left (4 \, b x + 4 \, a\right ) \sin \left (2 \, b x + 2 \, a\right ) + 4 \, \sin \left (2 \, b x + 2 \, a\right )^{2} + 4 \, \cos \left (2 \, b x + 2 \, a\right ) + 1\right )} \log \left (\frac {\cos \left (b x + 2 \, a\right )^{2} + \cos \relax (a)^{2} - 2 \, \cos \relax (a) \sin \left (b x + 2 \, a\right ) + \sin \left (b x + 2 \, a\right )^{2} + 2 \, \cos \left (b x + 2 \, a\right ) \sin \relax (a) + \sin \relax (a)^{2}}{\cos \left (b x + 2 \, a\right )^{2} + \cos \relax (a)^{2} + 2 \, \cos \relax (a) \sin \left (b x + 2 \, a\right ) + \sin \left (b x + 2 \, a\right )^{2} - 2 \, \cos \left (b x + 2 \, a\right ) \sin \relax (a) + \sin \relax (a)^{2}}\right ) - 4 \, {\left (\cos \left (3 \, b x + 3 \, a\right ) - \cos \left (b x + a\right )\right )} \sin \left (4 \, b x + 4 \, a\right ) + 4 \, {\left (2 \, \cos \left (2 \, b x + 2 \, a\right ) + 1\right )} \sin \left (3 \, b x + 3 \, a\right ) - 8 \, \cos \left (3 \, b x + 3 \, a\right ) \sin \left (2 \, b x + 2 \, a\right ) + 8 \, \cos \left (b x + a\right ) \sin \left (2 \, b x + 2 \, a\right ) - 8 \, \cos \left (2 \, b x + 2 \, a\right ) \sin \left (b x + a\right ) - 4 \, \sin \left (b x + a\right )}{32 \, {\left (b \cos \left (4 \, b x + 4 \, a\right )^{2} + 4 \, b \cos \left (2 \, b x + 2 \, a\right )^{2} + b \sin \left (4 \, b x + 4 \, a\right )^{2} + 4 \, b \sin \left (4 \, b x + 4 \, a\right ) \sin \left (2 \, b x + 2 \, a\right ) + 4 \, b \sin \left (2 \, b x + 2 \, a\right )^{2} + 2 \, {\left (2 \, b \cos \left (2 \, b x + 2 \, a\right ) + b\right )} \cos \left (4 \, b x + 4 \, a\right ) + 4 \, b \cos \left (2 \, b x + 2 \, a\right ) + b\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 0.17, size = 36, normalized size = 1.06 \[ \frac {\mathrm {atanh}\left (\sin \left (a+b\,x\right )\right )}{16\,b}-\frac {\sin \left (a+b\,x\right )}{16\,b\,\left ({\sin \left (a+b\,x\right )}^2-1\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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